0.5x^2-5.5x+14=0

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Solution for 0.5x^2-5.5x+14=0 equation:



0.5x^2-5.5x+14=0
a = 0.5; b = -5.5; c = +14;
Δ = b2-4ac
Δ = -5.52-4·0.5·14
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.5)-\sqrt{2.25}}{2*0.5}=\frac{5.5-\sqrt{2.25}}{1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.5)+\sqrt{2.25}}{2*0.5}=\frac{5.5+\sqrt{2.25}}{1} $

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